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33x-x^2-136=0
We add all the numbers together, and all the variables
-1x^2+33x-136=0
a = -1; b = 33; c = -136;
Δ = b2-4ac
Δ = 332-4·(-1)·(-136)
Δ = 545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{545}}{2*-1}=\frac{-33-\sqrt{545}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{545}}{2*-1}=\frac{-33+\sqrt{545}}{-2} $
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